Märklin turnout r=1.394 and angle

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Märklin turnout r=1.394 and angle - 10° or 15°?

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aclassifier		#1 Posted : 18 February 2021 10:37:01(UTC) Retweet
Joined: 18/03/2012(UTC) Posts: 156 Location: Trondheim		Hi, the Märklin turnout 59088 (left, r=1.394m) [1] says 10° angle (as does the 2019-2020 full range catalog). However, the 59087 (right) [2] says 15°. The necessary end piece 59092 [3] says "Frog Area 15°." Is it correct to assume that either of those turnouts plus the end piece will as a sum cover 15°? Øyvind [1] https://www.maerklin.de/en/products/details/article/59088 [2] https://www.maerklin.de/en/products/details/article/59087 [3] https://www.maerklin.de/en/products/details/article/59092
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H0		#2 Posted : 18 February 2021 12:50:48(UTC) Retweet
Joined: 16/02/2004(UTC) Posts: 15,443 Location: DE-NW		The German text reads "15°" for both turnouts. Maybe a copy'n'paste error with the English version.
		Regards Tom --- "In all of the gauges, we particularly emphasize a high level of quality, the best possible fidelity to the prototype, and absolute precision. You will see that in all of our products." (from Märklin New Items Brochure 2015, page 1) ROFLBTCUTS

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Purellum		#3 Posted : 18 February 2021 12:51:32(UTC) Retweet
Joined: 08/11/2005(UTC) Posts: 3,528 Location: Mullerup, 4200 Slagelse		Originally Posted by: aclassifier Is it correct to assume that either of those turnouts plus the end piece will as a sum cover 15°? Yes, there's clearly an error in the catalog and on the web page Per.
		If you can dream it, you can do it! I, the copyright holder of this work, hereby release it into the public domain. This applies worldwide. In case this is not legally possible: I grant anyone the right to use this work for any purpose, without any conditions, unless such conditions are required by law.

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aclassifier		#4 Posted : 19 February 2021 17:17:40(UTC) Retweet
Joined: 18/03/2012(UTC) Posts: 156 Location: Trondheim		Thanks, guys! And the conclusion is.. that 59087/59088 + 59092 = 15°?
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Purellum		#5 Posted : 19 February 2021 18:30:12(UTC) Retweet
Joined: 08/11/2005(UTC) Posts: 3,528 Location: Mullerup, 4200 Slagelse		Originally Posted by: aclassifier And the conclusion is.. that 59087/59088 + 59092 = 15°? Yes Per.
		If you can dream it, you can do it! I, the copyright holder of this work, hereby release it into the public domain. This applies worldwide. In case this is not legally possible: I grant anyone the right to use this work for any purpose, without any conditions, unless such conditions are required by law.

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