As promised, this is my way of improving ICE lighting, step by step
This is only for digital operation.
At first I removed all electronics. I found that it was causing noticeable voltage drops. I replaced it with a Lokpilot decoder, maximum voltage across motor increased by at least 30%.
Function F1 output drives the coil of a 12 V relais which connects the light feeder (yellow cable crossing all the train) to pickup shoe, so that a lot of power is available for lighting without loading the decoder.
Current return is through the wheels. In this way lights shine much more than before but current consumption is terrible, ~150 mA per coach. Each time I turn on lighting all trains on the layout slow down, particularly the ones with C-sinus2.

Then I replaced lamps with white LEDs.
Two SMD LEDs are placed on both sides of a 0.7 mm thin pcb (hand milled with a Dremel). These are high brightness (>700 mcd, 120 deg angle) LEDs in PLCC2 or PLCC4 package, beware of the PLCC4 padout.
The LEDs are connected in series, see the jumper between the two sides.

The assembly is placed in place of the lamp, but the lamp socket is used only as mechanical holder, there is no electrical connection between socket and LEDs (cuts on the LED pcb).

I removes the metal sheets across the lamps, could cause shorts, inserted both assemblies and closed the diffusion lens.

Connected the two assemblies in series

The supply voltage is now a digital signal with alternating polarity, I used a full wave rectifier and a constant current regulator, so that light is constant even with changing voltage on rails.
Connected the rectifier input to yellow and brown wires. If you want a simpler solution just use a ~500 ohm resistor in series to the LEDs (after the rectifier of course), otherwise, for electronics minded people,this is my complex solution:
a constant current source based on a current mirror.
FET BFR30 keeps current in right arm nearly constant at ~6 mA, which is multiplied by the mirror by ~ R2/R1.
If you put a trimmer as R2 you can adjust LED current. Why this arrangement ? It keeps LED current nearly constant with a minimum voltage drop. Here R1 = 10 ohms, R2 = 39 ohms, so that LED current ~20 mA
This is the result : five coaches draw less current than one with lamps

If you don't see the picture, try again later. It's the wonderful Alice, you can't disturb a lady...
Regards
Mario