Nice conversion. The only thing I would recommend is that you do put a small diode (I suggest a 1N4148 which are really small) in the reverse direction across the two LEDs. You will need only one diode. This will protect the LEDs against the reverse voltage during the other half of the sinewave.



The other option is to wire the two LEDs in parallel, but long wire to short wire, then the LEDs protect each other, as one conducts on one half of the sinewave, and the other conducts on the other half of the sinewave. You will not need to change the resistor values if you do this as the change in brightness will be negligible.

I recommend you do one of these adjustments as I wouldn't be happy long term operating LEDs with that much reverse voltage across them, as they will eventually fail due to the amplitude of the reverse voltage. Either solution above will limit this voltage to less than the manufacturers recommended maximum reverse voltage which is usually around 5-6 volts.

Quote : The other option is to wire the two LEDs in parallel, but long wire to short wire, then the LEDs protect each other.

Aren`t two LEDs already connected in parallel (long leg to short leg as shown in my diagram) ? If so, it solves the problem as suggested by you, if I misunderstood, I will have to incorporate a diode.
Thank you.

That is exactly what it is there to do. This way the maximum reverse voltage across the LEDs is around 0.6V, the forward voltage drop of the diode. Quite a standard way of protecting against reverse voltage, but does mean that the resistors are carrying current on both halves of the sinewave, so their power dissipation is doubled. however in this application the dissipation will be so low that this will not be a proble,.

P.S. what is the source of the LEDs you used in the Kittel, I have a couple of these to modify.