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tulit Offline
#1 Posted : 12 August 2012 22:17:29(UTC)
tulit

Canada   
Joined: 20/05/2012(UTC)
Posts: 185
Hi all.

I'd like to place a roundhouse with 15 degree separation between sheds without the need for a turntable.

Is there any ideal setup? This is what I came up with. It's giving 12.9 degrees which is pretty close. Is there anyway I can get closer or a more optimal setup?
tulit attached the following image(s):
roundhouse.png
60904 Offline
#2 Posted : 13 August 2012 07:02:40(UTC)
60904


Joined: 27/11/2007(UTC)
Posts: 154
Hi,

why don't you cut the curved track you need to get the 15°? Maybe you can even shorten the turnout to 15°.
Greetings
Martin
tulit Offline
#3 Posted : 13 August 2012 17:27:50(UTC)
tulit

Canada   
Joined: 20/05/2012(UTC)
Posts: 185
Originally Posted by: 60904 Go to Quoted Post
Hi,

why don't you cut the curved track you need to get the 15°? Maybe you can even shorten the turnout to 15°.



I think it will be pretty tricky to be able to cut and then attach C-track that precisely.

I wonder if switching to K-track (via a transition) for this area of the layout would be another choice (I think I can get the geometry right).

Or maybe this slightly wrong angle isn't such a huge deal and the trains will still fit into the shed?
Nielsenr Offline
#4 Posted : 14 August 2012 05:41:43(UTC)
Nielsenr

United States   
Joined: 06/10/2010(UTC)
Posts: 728
Location: Fort Lauderdale, FL
Hi,

I can't see what tracks you are using from your diagram. But the 24630 turnouts are 24.3 degrees like the standard 246XX turnouts. So why don't you use the 24206 (5.7 degrees) to get to the full 30 degrees and then put a 24215 (15 degrees) in the other direction to bring you back down to a perfect 15 degrees??

Robert
Xaurus Offline
#5 Posted : 18 September 2012 23:51:32(UTC)
Xaurus

Sweden   
Joined: 10/08/2012(UTC)
Posts: 32
Hi,

From Märklin's own manual for 72883 they suggest one piece of 24107 for each of the turns (the outer tracks). This is what I am going for in my own layout.

This gives 16,8 degrees but is sufficient for 72883 at least.

Best,
Martin
LeoArietis Offline
#6 Posted : 26 September 2012 19:56:32(UTC)
LeoArietis

Sweden   
Joined: 07/02/2008(UTC)
Posts: 94
Location: Lindome, Sweden
Using a dremmel-tool to cut through the rails, and cool with a wet sponge, then saw the curved track in three pieces. Remove the middlepart and put the end-parts together. Join with hot-glue and steel-wire.

See this post for building a hosen-träger.
http://www.svensktmjforu.../index.php?topic=10990.0
hxmiesa Offline
#7 Posted : 15 November 2012 12:09:34(UTC)
hxmiesa


Joined: 15/12/2005(UTC)
Posts: 2,232
Location: Spain
Originally Posted by: Xaurus Go to Quoted Post
From Märklin's own manual for 72883 they suggest one piece of 24107 for each of the turns (the outer tracks). This is what I am going for in my own layout.
This gives 16,8 degrees but is sufficient for 72883 at least.

This is the right answer! You can just "break" or "gap" the track a little, where the 7,5º connects to the switch and to the straight. Each "break" will be 0,9º, which will be almost invisiblea and represent no problem for the rolling stock, -and which will be held in place if the track is screwed down. That´s how you get 15º with no hassle and no problems.
Best regards
Henrik Hoexbroe ("The Dane In Spain")
http://hoexbroe.tripod.com
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